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NAT LAB #7 - flintlock - 12-17-2009
How2Pass Network is going to provide Internet access to all hosts in its LAN without changing the IP addresses configured on its internal hosts and servers. The company has 14 hosts that need access to the Internet simultaneously. The hosts have been assigned private addresses space in the range of 192.168.58.17 ? 192.168.58.30.
My question is - if the address range is indeed supposed to be 192.168.58.17 - 192.168.58.30, then why is the command in the NAT SIM LAB:
access-list 2 permit 192.168.58.16 0.0.0.15
I would think it would instead be 192.168.58.17?
Re: NAT LAB #7 - forumsupport - 12-18-2009
192.168.58.16 = subnet ID
0.0.0.15 = Wildcard mask
The combination specifies address range of 192.168.58.17 ? 192.168.58.30
Please read your book for more info on wildcard mask.