QID: RTE029 - Printable Version +- How2pass.com Forums (https://www.how2pass.com/forum) +-- Forum: CCNP (https://www.how2pass.com/forum/forum-6.html) +--- Forum: CCNP ENARSI 300-410 Forum (https://www.how2pass.com/forum/forum-15.html) +--- Thread: QID: RTE029 (/thread-512.html) |
QID: RTE029 - j3ncr1ck8t - 11-30-2010 Routing is definitely not a strength of mine; I've calculated the FD and AD for this question a few times and I have only come up with two paths A D E H and A F E H; am I missing something in why the answer is 3? Thanks, Jen Re: QID: RTE029 - senthilcbe - 12-20-2010 The answer is 2. The DC will get 2 routes 1 successor and 1 feasible successor. Anyone gives detail that this is wrong can explain. Thanks SK Re: QID: RTE029 - senthilcbe - 12-20-2010 AFTER HOURS TOGETHER CONFIGURED THE ROUTERS AND ASSIGNED WITH IP"S i found the result.... just go through this you will get the ans P 60.0.0.0/8, 1 successors, FD is 263680, serno 318 via 40.0.0.2 (263680/261120), Ethernet0/1, serno 313 via 10.0.0.2 (271360/261120), Ethernet0/0 via 70.0.0.2 (266240/261120), Ethernet0/2 P 70.0.0.0/8, 1 successors, FD is 261120, serno 3 via Connected, Ethernet0/2 via 10.0.0.2 (276480/266240), Ethernet0/0 P 80.0.0.0/8, 1 successors, FD is 266240, serno 229 via 70.0.0.2 (266240/261120), Ethernet0/2 via 40.0.0.2 (268800/266240), Ethernet0/1 via 10.0.0.2 (276480/266240), Ethernet0/0 P 90.0.0.0/8, 1 successors, FD is 271360, serno 320 via 70.0.0.2 (271360/266240), Ethernet0/2, serno 305 via 10.0.0.2 (279040/268800), Ethernet0/0 via 40.0.0.2 (273920/271360), Ethernet0/1 P 100.0.0.0/8, 1 successors, FD is 263680, serno 322 via 40.0.0.2 (263680/261120), Ethernet0/1 via 70.0.0.2 (266240/261120), Ethernet0/2 via 10.0.0.2 (268800/258560), Ethernet0/0 P 101.0.0.0/8, 2 successors, FD is 263680, serno 323 via 70.0.0.2 (263680/258560), Ethernet0/2 via 40.0.0.2 (263680/261120), Ethernet0/1 via 10.0.0.2 (271360/261120), Ethernet0/0 Best of Luck to all SK |