how to tackle this route summarization qs? - Printable Version +- How2pass.com Forums (https://www.how2pass.com/forum) +-- Forum: CCNA (https://www.how2pass.com/forum/forum-4.html) +--- Forum: General (https://www.how2pass.com/forum/forum-9.html) +--- Thread: how to tackle this route summarization qs? (/thread-517.html) |
how to tackle this route summarization qs? - kelvinwgr - 12-14-2010 10.0.0.0 10.0.1.0 10.0.2.0 10.0.3.0 what is the most appropriate summarization for these routes? a) 10.0.0.0/21 b) 10.0.0.0/22 c) 10.0.0.0/23 d) 10.0.0.0/24 Re: how to tackle this route summarization qs? - kelvinwgr - 12-14-2010 well i think i got it. the answer is (b). Re: how to tackle this route summarization qs? - ciscok1d - 01-12-2011 (12-14-2010, 03:31 PM)kelvinwgr link Wrote:well i think i got it. the answer is (b). Same answer I got and Im confident its correct. My method: 8 + 8 +6(common bits) = /22 00001010.00000000.000000|00.00000000 00001010.00000000.000000|00.00000000 00001010.00000000.000000|01.00000000 00001010.00000000.000000|10.00000000 00001010.00000000.000000|11.00000000 10 . 0 . 0 . 0 /22 So the first two octets are common between all 4 and are 8 bits each so 8+8 = 16 Also the 3rd octet has 6 bits in common with all 4 addresses as shown above, 16+6 = 22 so 10.0.0.0/22 is the answer Re: how to tackle this route summarization qs? - Hondabuff - 01-30-2012 The faster way with no Binary Math is: This will blow your mind how easy it is. 1) Find the Block size to cover all of the networks in the 3rd octet= Networks 0,1,2,3 answer is 4 block size. 2) Now count on your fingers backwards: 128,64,32,16,8,4, Should have 6 fingers sticking up. 3) How many common bits in the first 2 octets, 8+8= 16, Now add your like bits from your finger counting 16+6=22 4) Answer is 10.0.0.0/22 5) Again, no binary math and it all works from your 128,64,32,16,8,4,2,1 chart For example: Summarize these networks? 172.16.16.0 172.16.17.0 ................ ................ 172.16.25.0 1) What block size covers the all of the 3rd octets? Answer is 16 2) Count backwards on your fingers: 128,64,32,16 3) 4 fingers are up, added to the first 16bits. 8+8+4=20 4) Block size started at 16 so the answer is 172.16.16.0/20 Re: how to tackle this route summarization qs? - denyzenuk - 05-16-2012 @ Hondabuff Could you use your method on 10.1.2.0 10.1.7.0 10.1.9.0 Do you have to count block from subnet boundary? Re: how to tackle this route summarization qs? - denyzenuk - 05-16-2012 opps.. block that covers meaning > than not = to. thanks. Re: how to tackle this route summarization qs? - Hondabuff - 05-28-2012 Could you use your method on 10.1.2.0 10.1.7.0 10.1.9.0 10.1.{0-8 not enough because of the 9, 0-16 will cover all of 0-2-9-16} .0 All routes from 1-15 will be included because of the overage. Technically it would be considered a poorly designed network. 0-8, 0-16, 0-32, looks like all we need is 16 places to cover them all. We will be wasting places because the 10.1.9.0 is in the next block of 8. So a summarized network of 10.1.0.0/20. A block size of 16 is a 240 mask. The 10.1 make up 16 bits allready and 240 mask uses 4 bits. 16+4=/20 |