10-12-2012, 12:33 PM
The given explanation is clear enough but here I try again:
Please note that multiples of the increment 8 are subnet IDs, i.e. they are network addresses or subnet addresses and you cannot use them as host addresses.
subnet mask = /29 = 255.255.255.248
subnet increment = 256 - 248 = 8
Therefore, subnet IDs are in multiples of 8.
Here subnet ID: 192.168.20.24/29
Subnet host address range: 192.168.20.25 - 192.168.20.30
Broadcast address: 192.168.20.31
So the first usable host address is 192.168.20.25 = default gateway address.
Please note that multiples of the increment 8 are subnet IDs, i.e. they are network addresses or subnet addresses and you cannot use them as host addresses.
subnet mask = /29 = 255.255.255.248
subnet increment = 256 - 248 = 8
Therefore, subnet IDs are in multiples of 8.
Here subnet ID: 192.168.20.24/29
Subnet host address range: 192.168.20.25 - 192.168.20.30
Broadcast address: 192.168.20.31
So the first usable host address is 192.168.20.25 = default gateway address.