QID: RTE029

[j3ncr1ck8t]

Routing is definitely not a strength of mine; I've calculated the FD and AD for this question a few times and I have only come up with two paths A D E H and A F E H; am I missing something in why the answer is 3?

Thanks,
Jen

[senthilcbe]

The answer is 2.

The DC will get 2 routes 1 successor and 1 feasible successor.

Anyone gives detail that this is wrong can explain.

Thanks
SK

[senthilcbe]

AFTER HOURS TOGETHER CONFIGURED THE ROUTERS AND ASSIGNED WITH IP"S i found the result.... just go through this you will get the ans

P 60.0.0.0/8, 1 successors, FD is 263680, serno 318
        via 40.0.0.2 (263680/261120), Ethernet0/1, serno 313
        via 10.0.0.2 (271360/261120), Ethernet0/0
        via 70.0.0.2 (266240/261120), Ethernet0/2
P 70.0.0.0/8, 1 successors, FD is 261120, serno 3
        via Connected, Ethernet0/2
        via 10.0.0.2 (276480/266240), Ethernet0/0
P 80.0.0.0/8, 1 successors, FD is 266240, serno 229
        via 70.0.0.2 (266240/261120), Ethernet0/2
        via 40.0.0.2 (268800/266240), Ethernet0/1
        via 10.0.0.2 (276480/266240), Ethernet0/0
P 90.0.0.0/8, 1 successors, FD is 271360, serno 320
        via 70.0.0.2 (271360/266240), Ethernet0/2, serno 305
        via 10.0.0.2 (279040/268800), Ethernet0/0
        via 40.0.0.2 (273920/271360), Ethernet0/1
P 100.0.0.0/8, 1 successors, FD is 263680, serno 322
        via 40.0.0.2 (263680/261120), Ethernet0/1
        via 70.0.0.2 (266240/261120), Ethernet0/2
        via 10.0.0.2 (268800/258560), Ethernet0/0
P 101.0.0.0/8, 2 successors, FD is 263680, serno 323
        via 70.0.0.2 (263680/258560), Ethernet0/2
        via 40.0.0.2 (263680/261120), Ethernet0/1
        via 10.0.0.2 (271360/261120), Ethernet0/0

Best of Luck to all
SK